CO(g)+H2O(g)⇌CO2(g)+H2(g)(Initially)3100(At Equilibrium)3−x1−xxx
Kc=[CO2][H2][CO][H2O]=x2(3−x)(1−x) or,
1=x23−3x−x+x2 or,
x2=x2−4x+3
On solving, we get, x=0.75
∴ Moles of hydrogen at equilibrium =0.75
Now, we know that partial pressure (p) =Moles of substanceTotal number of moles×Total P
∴pH2=0.754×2=0.375 atm