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Byju's Answer
Other
Quantitative Aptitude
Coordinate Geometry
The value of ...
Question
The value of k for which the centres of the circles x
2
+ y
2
= 1, x
2
+ y
2
+ 6x – 2y = 1 and x
2
+ y
2
– 6kx + 4y – 1 = 0 are collinear, is __________.
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Solution
Centre
of
x
2
+
y
2
=
1
is
0
,
0
Centre
of
x
2
+
y
2
+
6
x
-
2
y
=
1
is
-
3
,
1
and
centre
of
x
2
+
y
2
-
6
k
x
+
4
y
-
1
is
3
k
,
-
2
are
collinear
i
.
e
.
0
0
1
-
3
1
1
3
k
-
2
1
=
0
i
.
e
.
area
of
triangle
with
three
collinear
points
is
zero
.
i
.
e
.
6
-
3
k
=
0
i
.
e
.
3
k
=
6
i
.
e
.
k
=
2
Suggest Corrections
3
Similar questions
Q.
The centres of the circles
x
2
+
y
2
=
1
,
x
2
+
y
2
+
6
x
−
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y
=
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and
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Q.
Prove that the centres of the three circles x
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+ 2x + 4y − 10 = 0 and x
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Q.
Find the radical centre of the three circles
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y
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5
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+
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−
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Q.
The centres of the circles
x
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=
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,
x
2
+
y
2
+
6
x
−
2
y
=
1
and
x
2
+
y
2
−
12
x
+
4
y
=
1
are
Q.
The radical centre of the circles
x
2
+
y
2
−
4
x
−
6
y
+
5
=
0
,
x
2
+
y
2
−
2
x
−
4
y
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1
=
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,
x
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lies on the line
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