The value of ‘k’ for which the points (1, 2), (5, 6) and (k, 1) are collinear is
0
If three points are collinear, then they lie on the same line.
Equation of the line passing through (1, 2) and (5, 6) is x-y+1=0.
Substituting the point (k, 1) in the line equation we get k = 0.