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Question

The value of k for which the points (7,-2), (5, 1), (3, k) collinear is _____.
  1. 4

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Solution

The correct option is A 4
Let A(7,2), B(5,1) & C(3,k) be the vertices of a triangle.

Condition for collinear points, ar(ABC)=0
Area of triangle having coordinates (x1,y1), (x2,y2), (x3,y3) is
12×|x1(y2y3)+x2(y3y1)+x3(y1y2)|


12|7(1k)+5(k+2)+3(21)|=077k+5k+10+(6)3=0179+5k7k=082k=02k=8k=82k=4

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