The value of $k$ , for which the system of equation $k x + 2 y = 5, 3 x + y = 1$ has no solution , is

5

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\frac{2}{3}

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6

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\frac{3}{2}

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Solution

The correct option is C $6$
$k x + 2 y = 5$ and $3 x + y = 1$ have no solution then
$∴ \frac{k}{3} = \frac{2}{1} \neq \frac{5}{1}$
$\frac{k}{3} = \frac{2}{1}$
$k = 6$

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