Question

The value of k for which the system of equations has no solution is

$$\begin{gathered} x+2y=5 \\ 3x+ky+15=0 \end{gathered}$$

(a) 6
(b) −6
(c) 3/2
(d) None of these

Answer 1

The given system of equation is

If then the equation have no solution.

By cross multiply we get

Hence, the correct choice is.