The value of $k$ if $k^{2} + 16 = 25$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 3
$k^{2} + 16 = 5 k^{2} = 25 - 16 k^{2} = 9 k = 3$

Suggest Corrections

Similar questions

Let a*b denote the length of the hypotenuse of a right angle triangle whose remaining two sides have length a, b. If (12*16)*k=25 then find the value of k2.

Q. Find the value of

k

x - 3

is a factor of

k^{2} x^{3} - k x^{2} + 3 k x - k

Q. For the equation

x^{2} + 2 x k + k^{2} = 0

, find the value of

k

x = 3

Q.
If

lim x \to 4 \frac{4 x + 3}{x - 2}

has value

\frac{k}{2} .

Find

k

Q. If

\sum_{k = 1}^{m} (k^{2} + 1) (k!) = 1999 (2000!)

, then the value of

m

Join BYJU'S Learning Program

The value of k if k2+16=25

The correct option is D 3k2+16=5k2=25−16k2=9k=3

The value of $k$ if $k^{2} + 16 = 25$

The correct option is D 3
$k^{2} + 16 = 5 k^{2} = 25 - 16 k^{2} = 9 k = 3$