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Byju's Answer
Standard XII
Chemistry
Lattice Energy
The value of ...
Question
The value of
(
K
p
/
K
c
)
for the reversible reaction
S
O
2
(
g
)
+
1
2
O
2
(
g
)
⇔
S
O
3
(
g
)
at constant temperature T is:
A
(
R
T
)
1
2
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B
RT
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C
(
R
T
)
−
1
2
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D
1
R
T
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Solution
The correct option is
C
(
R
T
)
−
1
2
The relationship between
K
p
and
K
c
is
K
p
=
K
c
(
R
T
)
Δ
n
.
For the reaction
S
O
2
(
g
)
+
1
2
O
2
(
g
)
⇔
S
O
3
(
g
)
,
The value of
Δ
n
is
1
−
(
1
+
1
2
)
=
−
1
2
.
Substitute this value in the above expression.
K
p
=
K
c
(
R
T
)
Δ
n
=
K
c
(
R
T
)
−
1
2
.
Hence,
K
p
K
c
=
(
R
T
)
−
1
2
.
Option C is correct.
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Similar questions
Q.
For the reaction
C
O
(
g
)
+
(
1
/
2
)
O
2
(
g
)
⇌
C
O
2
(
g
)
,
K
p
/
K
c
is
Q.
The ratio of
K
p
/
K
c
for the reaction,
C
O
(
g
)
+
1
2
O
2
(
g
)
⇌
C
O
2
(
g
)
is
Q.
The ratio of value of
K
p
K
c
for the reaction,
C
O
(
g
)
+
1
2
O
2
(
g
)
⇌
C
O
2
(
g
)
is:
Q.
A reversible reaction:
S
O
2
(
g
)
+
N
O
2
(
g
)
⇋
S
O
3
(
g
)
+
N
O
(
g
)
..
(
1
)
, takes place in two reversible steps as given below with equilibrium constant values
2.0
and
0.45
respectively.
S
O
2
(
g
)
+
1
2
O
2
(
g
)
⇋
S
O
3
(
g
)
,
K
=
2.0......
(
2
)
N
O
2
(
g
)
⇋
N
O
(
g
)
+
1
2
O
2
(
g
)
,
K
=
0.45......
(
3
)
The equilibrium constant
K
c
for reaction
(
1
)
is:
Q.
The relation between
K
p
and
K
c
of a reversible reaction at fixed temperature is
K
p
=
K
c
(
R
T
)
Δ
n
.
If true enter 1, if false enter 0.
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