Question

# The value of Kp1 and Kp2 for the reactions X⇌y+z→(1) And A⇌2B→(2) Are in the ratio of 9:1. If degree of dissociation of X and A be equal, then total pressure at Equilibrium (1) and (2) are in the ratio  36 : 11 : 91 : 13 : 1

Solution

## The correct option is A 36 : 1Suppose total pressure at equilibrium for reactions (1) and (2) are P1 and P2 respectively Then X⇌Y+.Z Initial 1 mole                         0               0  At Equilibrium 1−α   α   α ∴ Total =1+α Px=1−α1+αP1,Py=α1+αP1 And Pz=α1+αP1 Kp1=(α1+αP1)21−α1+αP1=α2P11−α2=α2P1 A⇌2B Initial             1 mole          0 At Equilibrium 1−α   2α ∴ Total =1+α Kp2=(2α1+αP2)21−α1+αP2=4α21−α2P2 =4α2p2 Kp1Kp2=α2P14α2P2=P14P2=91 (given) Or, P1P2=361=36:1

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