Question

The value of $\lambda$ for which the expression $x^3+x^2-5x+\lambda$ wiI1 be divisible by $(x-2)$ is:

• A. $2$
• B. $-2$
• C. $-3$
• D. $4$

Answer 1

Answer: (B)

$-2$

$x^3+x^2$ -$5x$ + $\lambda$ is divisible by ($x-2$ )
Putting x = 2 in the given expression will give zero as remainder.
= $(2{)}^3+(2{)}^2-5\times 2+\lambda$ = $0$
= $8+4-10+\lambda$ = $0$
Hence, $\lambda$ = $-2$