The value of - such that vectors A -2 -6 -k- and B -6 -4 -k-are orthogonal is a - 2 - b -12 1c-36 u un

Given, nbsp;A=2î 6ĵ+k̂ nbsp;and B=6î 4ĵ+λk̂ For orthogonality of vectors, A·B=0 ⇒ (2î 6ĵ+k̂)·(6î 4ĵ+λk̂)=0 ⇒ 12+24+λ=0 ⇒λ= 36 Answer: (c) ...

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The value of $λ$ such that vectors
$\to A = 2^i - 6^j +^k$ and $\to B = 6^i - 4^j + λ^k$
are orthogonal is
$(a) 2 (b) - 12 (c) - 36 (d) - 2$

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For what value of $λ$ , the vectors $\to a = 2^i + λ^j +^k and \to b =^i + 2^j + 3^k are orthogonal.$

The value of $λ$ for which the vectors $3^i - 6^j +^k a n d 2^i - 4^j + λ^k$ are parallel,is

(a) $\frac{2}{3}$ (b) $\frac{3}{2}$ (c) $\frac{5}{2}$ (d) $\frac{2}{5}$

Find the value of $λ$ such that the vectors $\to a = 2^i + λ^j +^k a n d \to b =^i + 2^j + 3^k$ are orthogonal.

(a) 0

(b) 1

(d) $\frac{- 5}{2}$

\to a =^i -^j + 2^k, \to b = 2^i + 4^j +^k

\to c = λ^i +^j + μ^k

(λ, μ) =

\to a =^i -^j + 2^k

\to b = 2^i + 4^j +^k

\to c = λ^i +^j + μ^k

(λ, μ) =

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