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Question

The value of (0.3)(0.3)2(0.3)(0.2)+(0.2)(0.2)

A
0.1
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B
0.01
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C
1
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D
0.1×0.1
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Solution

The correct options are
B 0.1×0.1
D 0.01
0.3×0.32×0.3×0.2+0.2×0.2

=(0.3)22×0.3×0.2+(0.2)2

Using identity a22ab+b2=(ab)2

=(0.30.2)2

=(0.1)2

=0.1×0.1

=0.01.

The option B and D both are correct.

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