The value of 15 1-32 is equal to

The correct option is C 235 1/9 ( 15 1/3 )^2 can be written as ( 15 + 1/3 ) ( 15 + 1/3 ) = 15 × 15 + 15 ×1/3 + 1/3× 15 + 1/3×1/3 = 225 + 5 + 5 +1/9 = 235 1/9 ...

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Byju's Answer

Standard VIII

Mathematics

Multiplication of Binomials

The value of ...

Question

The value of ${(15 \frac{1}{3})}^{2}$ is equal to

$225 \frac{1}{9}$

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$245 \frac{1}{9}$

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$255 \frac{1}{9}$

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$235 \frac{1}{9}$

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Solution

The correct option is D
$235 \frac{1}{9}$

${(15 \frac{1}{3})}^{2}$ can be written as

$(15 + \frac{1}{3}) (15 + \frac{1}{3})$

$= 15 \times 15 + 15 \times \frac{1}{3} + \frac{1}{3} \times 15 + \frac{1}{3} \times \frac{1}{3}$

$= 225 + 5 + 5 + \frac{1}{9}$

$= 235 \frac{1}{9}$

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The value of (1513)2 is equal to

The correct option is D 23519 (1513)2 can be written as (15+13)(15+13) =15×15+15×13+13×15+13×13 =225+5+5+19 =23519

The value of ${(15 \frac{1}{3})}^{2}$ is equal to

The correct option is D
$235 \frac{1}{9}$

${(15 \frac{1}{3})}^{2}$ can be written as

$(15 + \frac{1}{3}) (15 + \frac{1}{3})$

$= 15 \times 15 + 15 \times \frac{1}{3} + \frac{1}{3} \times 15 + \frac{1}{3} \times \frac{1}{3}$

$= 225 + 5 + 5 + \frac{1}{9}$

$= 235 \frac{1}{9}$