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Question

The value of (21C110C1)+(21C210C2)+(21C310C3)+(21C410C4)+...+(21C1010C10) is

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Solution

(21C110C1)+(21C210C2)+(21C310C3)+(21C410C4)+...+(21C1010C10)=(21C1+21C2+21C3+.....21C10)I(10C1+10C2+10C3+...+10C10)2101I=21C1+21C2+21C3+.....21C10I=21C20+21C19+21C18+.....21C202I=21C1+21C2+21C3+.....+21C19+21C202I=2211I=22112=22012I2101=220122101=22021032

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