The value of 3-53 is a-5 then find a-

⇒(3√(5))^3=3^3(√(5))^3 =27× 5√(5)=135√(5)=a√(5) ∴ #160; a=135 ...

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Exponents with Like Bases

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The value of ${(3 \sqrt{5})}^{3}$ is $a \sqrt{5}$ then find $a$ .

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5 \sqrt{5} \times 5^{3} \div 5^{- \frac{3}{2}} = 5^{a + 2}

a

p = \frac{3 - \sqrt{5}}{3 + \sqrt{5}} and q = \frac{3 + \sqrt{5}}{3 - \sqrt{5}}

Find the value of $(3 + \sqrt{5}) (3 - \sqrt{5})$ .

a - b = 5

a^{2} + b^{2} = 53

a b

{(\frac{3^{0} \times 5^{3} \times 5^{- 3}}{3^{- 1}})}^{- 1}

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