The value of $(a + 1) (a - 1) (a^{2} + 1)$ is $a^{4} - 1$

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Solution

Value of

$(a + 1) (a - 1) (a^{2} + 1)$

$= (a^{2} - 1^{2}) (a^{2} + 1^{2})$

$= (a^{4} - 1^{4})$

$= (a^{4} - 1)$

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Similar questions

Q. Tick (✓) the correct answer:
(a + 1)(a − 1)(a² + 1) = ?
(a) (a⁴ − 2a² − 1)
(b) (a⁴ − a² − 1)
(c) (a⁴ − 1)
(d) (a⁴ + 1)

Tick $(✓)$ the correct answer in each of the following:
$(a + 1) (a - 1) (a^{2} + 1) = ?$
(a) $(a^{4} - 2 a^{2} - 1)$
(b) $(a^{4} - a^{2} - 1)$
(c) $(a^{4} - 1)$
(d) $(a^{4} + 1)$

Question 80

In the following question, state whether the statement is True (T) or False (F):

The value of $(a + 1) (a - 1) (a^{2} + 1)$ is $a^{4} - 1$ .

Q. State whether the statement is True or False:

On evaluating

(a + 1) (a - 1) (a^{2} + 1)

, the answer is

a^{4} - 1

Q. Find the product
(i)

(a + 1) (a - 1) (a^{2} + 1)

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The value of (a+1)(a−1)(a2+1) is a4−1

Value of (a+1)(a−1)(a2+1) =(a2−12)(a2+12) =(a4−14) =(a4−1)

The value of $(a + 1) (a - 1) (a^{2} + 1)$ is $a^{4} - 1$

Value of

$(a + 1) (a - 1) (a^{2} + 1)$

$= (a^{2} - 1^{2}) (a^{2} + 1^{2})$

$= (a^{4} - 1^{4})$

$= (a^{4} - 1)$