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Question

The value of ∣∣ ∣ ∣∣−a2abacab−b2bCacbC−c2∣∣ ∣ ∣∣ is

A
4abc
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B
4a2b2c2
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C
a2b2c2
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D
a2+b2+c2abbcca
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Solution

The correct option is B 4a2b2c2
Let A=∣ ∣ ∣a2abacabb2bcacbcc2∣ ∣ ∣

take common from rows

A=abc∣ ∣abcabcabc∣ ∣

No, take common from columns,

A=(abc)2∣ ∣111111111∣ ∣

By operation of matrix

A=(abc)2[1(11)1(11)+1(1+1)]

A=(abc)2(2+2)

A=4a2b2c2

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