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Question

The value of ∣ ∣ ∣b2c2bcb+cc2a2cac+aa2b2aba+b∣ ∣ ∣ is

A
4abc
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B
(ab)(bc)(ca)
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C
(a+b+c)3
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D
0
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Solution

The correct option is D 0
R1R1bc,R2R2ac,R3R3ab
∣ ∣ ∣ ∣bc11b+1cca11c+1aab11a+1b∣ ∣ ∣ ∣
CC1abcthen,C3C3+C1
∣ ∣ ∣ ∣1a11a+1b+1c1b11a+1b+1c1c11a+1b+1c∣ ∣ ∣ ∣=0
(Two columns identical)

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