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Question

The value of [cos4Asin4A] is equal to:

A
2cos2A+1
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B
2cos2A1
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C
2sin2A1
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D
2sin2A+1
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Solution

The correct option is B 2cos2A1
cos4Asin4A=(cos2Asin2A)(cos2A+sin2A)
=(cos2Asin2A).1
=cos2A(1cos2A)
=2cos2A1.
Hence, the answer is 2cos2A1.


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