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Question

The value of (1+i31i)30 is:

A
215i
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B
215
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C
215i
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D
65
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Solution

The correct option is C 215i
(1+i31i)30
=[(2ω1i)]30
=230ω30((1i)2)15
=2301(1+i22i)15
=230(2)15i15
=215i
=215ii2
=215i

Alternate Solution:
(1+i31i)30
=[(1+i32)(1+i)]30
=w30(1+i)30=(1+2i1)15
=215i

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