Question

The value of $[\frac{3}{4}\times \frac{4}{12}]+[\frac{3}{4}\times \frac{-3}{9}]$ is

• A. $\frac{3}{4}$
• B. $0$
• C. $1$
• D. $\frac{1}{2}$

Answer 1

The correct option is B $0$

$[\frac{3}{4}\times \frac{4}{12}]+[\frac{3}{4}\times \frac{-3}{9}]$
$=\frac{3}{4}\times [\frac{4}{12}+\frac{-3}{9}]$ ($\because$ distributive property)
$=\frac{3}{4}\times 0$
$=0$.