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Question

The value of (cosA+cosBsinA−sinB)n+(sinA+sinBcosA−cosB)n is

A
2tannAB2
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B
2cotnAB2:n is even
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C
0:n is odd
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D
none
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Solution

The correct option is C 0:n is odd
(cosA+cosBsinAsinB)n+(sinA+sinBcosAcosB)n(2cosA+B2cosA+B22cosA+B2sinA+B2)n+(2sin(A+B2)cos(AB2)2sinA+B2sinAB2)n[cotAB2]n+[cotAB2]n
If his odd its value is (0)

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