Question

The value of $\left(\frac{{\Delta }^2}{E}\right)x^2$ at the interval $h=1$ is

• A. $0$
• B. $1$
• C. $2$
• D. $4$

Answer 1

The correct option is A $0$

$\left(\frac{{\Delta }^2}{E}\right)x=\left(\frac{(E-1{)}^2}{E}\right)x$
$=\left(\frac{E^2-2E+1}{E}\right)x$
$=\frac{E^2\left(x\right)-2E\left(x\right)+x}{E\left(x\right)}$
$=\frac{(x+1)-2(x+1)+x}{(x+1)}$
$=\frac{0}{(x+1)}=0$