The value of 1-2log25 is equal to

The correct option is C 1/5 #160;Using #160; a^log _an= n #160; 1 / 2 #160;^log _ 2 5 #160;= 2 ^ log _ 2 5 #160;= 2 ^log _ 2 5 ^ ...

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Property 6

The value of ...

Question

The value of ${(\frac{1}{2})}^{{log}_{2} 5}$ is equal to

\frac{1}{5}

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\frac{- 1}{5}

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\frac{- 1}{25}

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\frac{1}{25}

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Solution

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Similar questions

\frac{5 \times {(25)}^{n + 1} + 25 \times {(5)}^{2 n - 1}}{25 \times {(5)}^{2 n} - 105 {(25)}^{n - 1}}

Simplified value of $(25)^{\frac{1}{3}} \times 5^{\frac{1}{3}}$

(a) 25 (b) 3 (c) 1 (d) 5

t_{5}, t_{10}

t_{25}

5^{t h}, 10^{t h}

25^{t h}

∣ ∣ ∣ ∣ \begin{matrix} t_{5} & t_{10} & t_{25} 5 & 10 & 25 1 & 1 & 1 \end{matrix} ∣ ∣ ∣ ∣

Question 1

$\frac{2}{5} \times 5 \frac{1}{5}$ is equal to
(a) $\frac{26}{25}$
(b) $\frac{52}{25}$
(c) $\frac{2}{5}$
(d) 6

\frac{5^{0} + 5^{- 1}}{5^{0} - 5^{- 1}} - {(\frac{8}{27})}^{\frac{1}{3}} - {(\frac{36}{25})}^{- \frac{1}{3}}

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