The value of [1(216)−13+1(256)−14+1(32)−25]
16
14
22
12
=[(216)13+(256)14+(32)25]=[(63)13+(44)14+(25)25]=[6+4+22]=14
14+04=____
If [2 1 3] ⎡⎢⎣−1 0 −1−1 1 00 1 1⎤⎥⎦⎡⎢⎣10−1⎤⎥⎦=A, then find the value of A.