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Question

The value of (tan1π+tan1(1π))+tan13sec1(2) is equal to

A
π3
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B
π6
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C
2π3
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D
π
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Solution

The correct option is B π6
(tan1π+tan1(1π))+tan13sec1(2)
=tan1π+cot1π+tan13sec1(2) [tan1(1y)=cot1y]
=π2+tan13sec1(2) [tan1x+cot1x=π2]
=π2+π32π3 [tanπ3=3;sec2π3=2]
=π2π3
=π6
None of the given options are correct.


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