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Question

The value of [ab bc ca]+[a×b b×c c×a] equals?

A
[abc]
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B
[abc]2
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C
0
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D
[abc]
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Solution

The correct option is C [abc]
[(ab)(bc)(ca)]+[a×b×c(c×a]{(ab)×(bc)}.(ca)+[(a×b).(c×a)]{a×ba×cb×b+b×c}.(ca)+[abc]2{a×b+c×a+b×c}.(c×a)+[abc]2{[abc]+[abc]}+[abc]2[a×b=(b×a)][a×a=0][abc]2

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