The value of - i- -j- -j- -k- -k- -i- is equal to-

The correct option is C 2 The Scalar triple #160; product can be written as: (i⃗+ j⃗).[(j⃗+k⃗)×(k⃗+i⃗)] = (i⃗+j⃗).(i⃗ k⃗+j⃗) =1+1=2 ...

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Unit Vectors

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The value of $[\to i + \to j, \to j + \to k, \to k + \to i]$ is equal to:

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