The value of limn- 12n-1-12n-2-16n is

Let S=lim_n→∞(12n+1+12n+2+⋯+16n) ⇒ S =lim_n→∞∑_r=1^4n12n+r =lim_n→∞1n·∑_r=1^4n12+ ( rn ) =∫_0^4dx2+x=[ ln | 2+x |]_0^4 =ln6 ln2=ln3 ...

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Right Hand Derivative

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The value of $lim n \to \infty (\frac{1}{2 n + 1} + \frac{1}{2 n + 2} + \dots + \frac{1}{6 n})$ is

ln 2

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ln 4

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ln 3

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ln 5

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