The value of limx→0([100xsin x]+[99sin xx]),where [.] denotes the greatest integer function, is
198
For x > 0, sin x < x
⇒sin xx<1
∴99sin xx<99
⇒[99sin xx] = 98
and xsin x>1
∴100xsin x>100
⇒[100xsin x] = 100
∴limx→0([100xsin x]+[99sin xx]) = 100+98 = 198