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Question

The value of limx0((1x)sin x), where x>0 is

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Solution

limx0[(1x)sin x]

For
limx0(1x)sin x=L , take log both sides .
logL=limx0sinxlog(1x)
L=elimx0logxcosecx

=elimx01xcosec x cot x [Using L 'Hospita's rule]

=elimx0sin xxtan x=e0=1

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