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Byju's Answer
Standard XII
Mathematics
Single Point Continuity
The value of ...
Question
The value of
lim
x
→
0
(
(
1
x
)
sin
x
)
, where
x
>
0
is
Open in App
Solution
lim
x
→
0
[
(
1
x
)
sin
x
]
For
lim
x
→
0
(
1
x
)
sin
x
=
L
, take log both sides .
log
L
=
lim
x
→
0
sin
x
log
(
1
x
)
⇒
L
=
e
lim
x
→
0
−
log
x
cosec
x
=
e
lim
x
→
0
−
1
x
−
cosec
x
cot
x
[
Using L 'Hospita's rule
]
=
e
lim
x
→
0
sin
x
x
tan
x
=
e
0
=
1
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Single Point Continuity
Standard XII Mathematics
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