Question

The value of ${lim}_{x\to 0}\frac{sin\alpha x+bx}{ax+sinbx}$ is $(a,b,a+b\ne 0)$

• A. 1
• B. a
• C. b
• D. a+b

Answer 1

The correct option is A

1

${lim}_{x\to 0}\frac{\frac{sinax}{x}+b}{a+\frac{sinax}{x}}=\frac{a+b}{a+b}=1$