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Question

The value of limx1x72x5+1x33x2+2


A
is 0
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B
is -1
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C
is 1
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D
Does not exist
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Solution

The correct option is C is 1
limx1[x72x5+1x33x2+2]=12+111+2=00
Apply L-Hospital's rule
=limx17x610x43x26x

= 1

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