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B
-1
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C
0
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D
1/2
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Solution
The correct option is C
0
limx→∞x55x=limx→∞x5exlog5=limx→∞x5ekx,where k=log5=limx→∞x5(1+kx+k2x22!+k3x33!+k4x44!+k5x55!+k6x66!+......)=limx→∞1[1x5+k.1x4+k22!.1x3+k33!.1x2+k44!.1x1+k55+(k66!x+......)]=0 As denominator is approaching to infinity.