Question

The value of limit $\underset{x\to \infty }{lim}\left[\frac{4x-3}{2x+7}\right]$ is

• A. $\infty$
• B. $0$
• C. $\frac{7}{3}$
• D. $2$

Answer 1

Answer: (D)

$2$

The value of the limit $\underset{x⟶\infty }{lim}\frac{4x-3}{2x+7}$ is

$=\underset{x\to \infty }{lim}\frac{x-(4-\frac{3}{x})}{x(2+\frac{7}{x})}$

$=\underset{x\to \infty }{lim}\frac{4-\frac{3}{x}}{2+\frac{7}{x}}$

$=\frac{4}{2}$

$=2$