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Question

The value of ((log29)2)1log2(log29)×(7)1log47 is

A
8
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B
4
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C
6
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D
10
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Solution

The correct option is A 8
((log29)2)1log2(log29)×(7)1log47
= (log29)2log2(log29)×(7)12log47
= (log29)2log(log29)2×(7)12log74
= (log29)log(log29)4×(7)log72
= 4×2
= 8


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