Question

The value of ${log}_{2\sqrt{3}}^{1728}$ is

• A. 3
• B. 5
• C. 6
• D. 9

Answer 1

The correct option is C 6

$1728=2^6\times 3^3=2^6\times (\sqrt{3}{)}^6=(2\sqrt{3}{)}^6$

${\log }_{2\sqrt{3}}1728={\log }_{2\sqrt{3}}(2\sqrt{3}{)}^6=6$