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Bricks Logarithm

The value of ...

Question

The value of
$l o g_{3} 4. l o g_{4} 5. l o g_{5} 6. l o g_{6} 7. l o g_{7} 8. l o g_{8} 9$ is

A

1

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B

2

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C

3

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D

4

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Solution

The correct option is B 2
$l o g_{3} 4. l o g_{4} 5. l o g_{5} 6. l o g_{6} 7. l o g_{7} 8. l o g_{8} 9$
$= \frac{l o g 4}{l o g 3} . \frac{l o g 5}{l o g 4} . \frac{l o g 6}{l o g 5} . \frac{l o g 7}{l o g 6} . \frac{l o g 8}{l o g 7} . \frac{l o g 9}{l o g 8}$
$= \frac{l o g 9}{l o g 3}$
$= l o g_{3} 9 = l o g_{3} 3^{2} = 2$

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Similar questions

l o g_{3} 4 . l o g_{4} 5 . l o g_{5} 6 . l o g_{6} 7 . l o g_{7} 8 . l o g_{8} 9

Q. Find the value of

l o g_{3} 4. l o g_{4} 5. l o g_{5} 6. l o g_{6} 7. l o g_{7} 8. l o g_{8} 9

.

Q. Find the value of

{log}_{3} 4. {log}_{4} 5. {log}_{5} 6. {log}_{6} 7. {log}_{7} 8. {log}_{8} 9

.

Q. Find the value of:

{log}_{3} 4. {log}_{4} 5. {log}_{5} 6. {log}_{5} 7. {log}_{7} 8. {log}_{7} 8. {log}_{8} 9.

{log}_{3} 4 \cdot {log}_{4} 5 \cdot {log}_{5} 6 \dots {log}_{n - 1} (n) = 4

, then the value of

n

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