Question

The value of $\log 4+\frac{1}{3}\log 125-\frac{1}{5}\log 32$ is equal to

• A. $7$
• B. $3$
• C. $1$
• D. $5$

Answer 1

The correct option is C $1$

$\log 4+\frac{1}{3}\log 125-\frac{1}{5}\log 32=\log 4+\log {125}^{\frac{1}{3}}-\log {32}^{\frac{1}{5}}=\log 4+\log 5-\log 2=\log \left(\frac{4\times 5}{2}\right)=\log 10\text{Assuming base 10},\log 10=1$