Question

The value of $\log 5+\log 8-2\log 2$ is equal to

• A. $1$
• B. $8$
• C. $4$
• D. $2$

Answer 1

The correct option is A $1$

$\log 5+\log 8-2\log 2=\log (5\times 8)-\log 2^2=\log \left(\frac{5\times 8}{2\times 2}\right)=\log \left(10\right)\text{Assuming base 10}\therefore {\log }_{10}10=1$