The value of $l o g_{9} 27 - l o g_{27} 9$ is

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\frac{3}{2}

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\frac{5}{6}

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None

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Solution

The correct option is C $\frac{5}{6}$
We have $(\frac{3}{2} - \frac{2}{3}) l o g_{3} 3 = \frac{5}{6}$

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l o g 27 = 1.431

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log \frac{9}{8} - log \frac{27}{32} + log \frac{3}{4}

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{log}_{27} {(2^{x} - 1)}^{3}

A . P .

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