The value of loga2-2 a b-b2- where a and b are consecutive natural numbers and a is greater than b isA- Depends only on the value of bB- Depends on the value of a and bC- Depends only on the value of aD- 0

The correct option is D 0 a = b + 1 log(a^2 2ab+b^2)=log(a b)^2 = 2 log(a b) = 2 log 1 = ...

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Question

The value of $l o g (a^{2} - 2 a b + b^{2})$ , (where a and b are consecutive natural numbers and a is greater than b) is

Depends on the value of a and b

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Depends only on the value of a

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Depends only on the value of b

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Solution

The correct option is B
0

a = b + 1

$l o g (a^{2} - 2 a b + b^{2}) = l o g (a - b)^{2}$

= 2 log(a-b)

= 2 log 1

= 0.

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The value of log(a2−2ab+b2), (where a and b are consecutive natural numbers and a is greater than b) is

The correct option is B 0 a = b + 1 log(a2−2ab+b2)=log(a−b)2 = 2 log(a-b) = 2 log 1 = 0.

The value of $l o g (a^{2} - 2 a b + b^{2})$ , (where a and b are consecutive natural numbers and a is greater than b) is

The correct option is B
0

a = b + 1

$l o g (a^{2} - 2 a b + b^{2}) = l o g (a - b)^{2}$

= 2 log(a-b)

= 2 log 1

= 0.