Question

The value of $\log \left(\frac{a^2}{bc}\right)+\log \left(\frac{b^2}{ca}\right)+\log \left(\frac{c^2}{ab}\right)$ is

• A. $0$
• B. $1$
• C. $ac$
• D. $bc$

Answer 1

Answer: (A)

$0$

We know $\log a+\log b=\log ab$

Therefore, the value of $\log \left(\frac{a^2}{bc}\right)+\log \left(\frac{b^2}{ca}\right)+\log \left(\frac{c^2}{ab}\right)$ is
$=\log (\frac{a^2}{bc}\times \frac{b^2}{ca}\times \frac{c^2}{ab})$

$=\log 1=0$