The value of m for which the pair of linear equation 4x + 6y - 1 = 0 and 2x + my - 7 = 0 represents parallel lines is

m = 3

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m = 2

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m = 4

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m = - 2

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Solution

The correct option is A $m = 3$
$4 x + 6 y - 1 = 0$ and $2 x + m y - 7 = 0$
Here $a_{1} = 4, a_{2} = 6, a_{3} = - 1$ and $a_{2} = 2, b_{2} = m, c_{2} = - 7$
As the given pair of linear equation represents parallel lines if
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}}$
$\Rightarrow \frac{4}{2} = 6 m$
$\Rightarrow m = \frac{2 \times 6}{4} = 3$
Hence the value of $m = 3$

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