The value of machinery is Rs.10000. The value is depreciating by 15% every year. What will be the value of the machinery after 2 years?

8225

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7225

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9225

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5225

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Solution

The correct option is B
7225

Amount on depreciation = Original amount $(1 - \frac{r}{100})^{n}$

= $10000 (1 - \frac{15}{100})^{2}$

= $10000 (\frac{85}{100})^{2}$

= Rs. 7225/-

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The value of machinery is Rs.10000. The value is depreciating by 15% every year. What will be the value of the machinery after 2 years?

The correct option is B 7225 Amount on depreciation = Original amount (1−r100)n = 10000(1−15100)2 = 10000(85100)2 = Rs. 7225/-

The correct option is B
7225

Amount on depreciation = Original amount $(1 - \frac{r}{100})^{n}$

= $10000 (1 - \frac{15}{100})^{2}$

= $10000 (\frac{85}{100})^{2}$

= Rs. 7225/-