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Question

The value of f(0) such f(x)=1cos2x+sin2xx2+11(x0) is continuous at x=0 is

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Solution

Given f(x)=1cos2x+sin2xx2+11(x0)
Since, f(x) is continuous at x=0
limx0f(x)=f(0)
limx01cos2x+sin2xx2+11
=limx02sin2xx2(x2+1+1)
=2limx0(sinxx)2limx0(x2+1+1)
=2×1×2=4
f(0)=4

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