Question

The value of $(n+1{)}^2-n^2$ is equal to

• A. $n+2$
• B. $2n+1$
• C. $2n+2$
• D. $n+1$

Answer 1

The correct option is B

$2n+1$

The given expression is

$(n+1{)}^2-n^2$

$(n+1{)}^2-n^2=(n+1)+n$

[Difference of square of two consecutive natural number is their sum]

$=2n+1$