Question

The value of ${}^{\prime }{n}^{\prime }$ for the parent and finally stable element obtained from the decay of $(4n+1)$ series respectively is:

• A. 60, 52
• B. 58, 54
• C. 58, 51
• D. 60, 54

Answer 1

The correct option is A 60, 52

The value of ${}^{\prime }{n}^{\prime }$ for the parent and finally stable element obtained from the decay of $(4n+1)$ series respectively is 60, 52. $(4n+1)$ series has parent element ${}^{241}\text{Pu}$ and ${}^{209}\text{Bi}$ is finally formed stable element.
When the mass number (241) of ${}^{241}\text{Pu}$ is divided by 4, the quotient is 60 and the remainder is 1.
When the mass number (209) of ${}^{209}\text{Bi}$ is divided by 4, the quotient is 52 and the remainder is 1.