The value of n in the following reaction is - Cr2O2-7 - ne- - 14 H- - 2Cr3-7H2O

The oxidation number of Cr changes from +6 in Cr_2O^2 _7 to +3 in Cr^3+ .The change in the oxidation number per Cr atom is 3 . ...

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Ion Electron Method

The value of ...

Question

The value of $n$ in the following reaction is :

$C r_{2} O_{7}^{2 -} + n e^{-} + 14 H^{+} \to 2 C r^{3 +} + 7 H_{2} O$

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^{'} n^{'}

C r_{2} O_{7}^{2 -} + 14 H^{+} + + n F e^{2 +} \to 2 C r^{3 +} + n F e^{3 +} + 7 H_{2} O

14 H^{+} + C r_{2} O_{7}^{2 -} + 3 N i \to 2 C r^{3 +} + 7 H_{2} O + 3 N i^{2 +} ?

14 H^{+} + C r_{2} O_{7}^{2 -} + 3 N i \to 2 C r^{3 +} + 7 H_{2} O + 3 N i^{2 +}

C r_{2} O_{7}^{2 -}

C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} 2 C r^{3 +} + 7 H_{2} O

14 H^{+} + C r_{2} O_{7}^{2 -} + 3 N i \to 2 C r^{3 +} + 7 H_{2} O + 3 N i^{2 +}

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