The value of n in the molecular formula $B e_{n} A l_{2} S i_{6} O_{18}$ is

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Solution

The correct option is B 3
The molecular formula of the given compound is $B e_{n} A l_{2} S i_{6} O_{18}$
n =?
Now, (2×n) + (3×2) + (4×6) + (-2×18) = 0
⇒ 2n + 6 + 24 – 36 = 0
⇒ 2n – 6 = 0
⇒ 2n = 6
⇒ n = 6/2
⇒ n = 3

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